
Welcome to your manual for Pips, the latest edition to the New York Times game lineup.
Released in August 2025, Pips introduces a distinctive take on dominoes, offering an enjoyable single-player gameplay experience that could turn into your new daily gaming habit.
At present, if you find yourself at a standstill, the game discloses the whole puzzle, necessitating you to move to the next difficulty tier and begin again. But don’t fret, we have you covered! Below are partial solutions that will act as clues to guide you through each difficulty tier.
How to engage with Pips
If you have played dominoes, you will grasp the fundamental mechanics of Pips. As noted in our earlier hints articles for Pips, the tiles, akin to dominoes, are arranged either vertically or horizontally and interconnect with one another. The primary distinction between classic dominoes and Pips is the color-coded criteria you must fulfill. The adjoining tiles do not necessarily need to correspond.
Wordle today: Solution, tips for November 8, 2025
The criteria you need to satisfy are particular to the color-coded zones. For instance, if it presents a singular figure, every side of a tile within that zone must total to the specified figure. It is feasible – and routine – for just half a tile to reside within a color-coded zone.
Here are frequent cases you will face across the difficulty tiers:
Number: All the pips in this area must sum up to the number.
Equal: Each domino half in this region must contain an identical number of pips.
Not Equal: Every domino half in this area must possess entirely distinct numbers of pips.
Less than: Each domino half in this space must accumulate to a figure less than the given number.
Greater than: Each domino half in this area must total to a number exceeding the given figure.
If a section lacks any color coding, it signifies there are no rules governing the sections of dominoes in those areas.
NYT Strands tips, solutions for November 8, 2025
Easy difficulty clues, solutions for Nov. 15 Pips
Number (2): All components in this red area must total 2. The solution