Welcome to your Pips guide, the latest entry in the New York Times games lineup.

Released in August 2025, Pips provides a novel twist on dominoes, offering an enjoyable single-player adventure that may turn into your new favorite daily gaming pastime.

Right now, if you find yourself stuck, the game permits only the option to unveil the complete puzzle, encouraging you to progress to the next level of difficulty and restart. However, fret not, we’re here to assist! Below are partial solutions that will serve as clues to guide you through each difficulty tier.

How to engage with Pips

If you’re familiar with dominoes, you’ll grasp the fundamentals of how Pips operates. As highlighted in our earlier hint articles regarding Pips, the tiles, akin to dominoes, can be arranged vertically or horizontally and should connect with one another. The key distinction between classic dominoes and Pips lies in the color-coded conditions that you need to meet. The adjacent tiles are not required to correspond.

The criteria you need to fulfill pertain specifically to the color-coded regions. For example, when a single number is displayed, the sum of every side of a tile within that region must equal the specified number. It is feasible – and often the case – that only a portion of a tile resides within a color-coded area.

Here are typical examples you will meet throughout the difficulty levels:

• Number: All the pips in this region must total the specified number.

• Equal: Each domino half in this region must have an identical number of pips.

• Not Equal: Each domino half in this region must feature entirely different numbers of pips.

• Less than: Each domino half in this region must sum to less than the specified number.

• Greater than: Each domino half in this region must total more than the specified number.

If a section is devoid of color coding, it implies that there are no stipulations concerning the segments of dominoes within those areas.

Easy difficulty hints, solutions for March 15 Pips

Equal (0): All elements in this area must equal 0. The solution is 0-